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第六章第三十六题(几何:正多边形的面积)(Geometry: area of a regular polygon) - 编程练习题答案

*6.36(几何:正多边形的面积)正多边形是一个n条边的多边形,它的每条边的长度都相等,而且所有角的角度也相等(即多边形既是等边又等角的)。计算正多边形面积的公式是:

使用下面的方法头编写方法,返回正多边形的面积:

public static double area(int n, double side)

编写一个main方法,提示用户输入边的个数以及正多边形的边长,然后显示它的面积。

下面是一个运行示例:

Enter the number of sides: 5

Enter the side:6.5

The area of the polygon is 72.690170
 

*6.36(Geometry: area of a regular polygon) A regular polygon is an n-sided polygon in which all sides are of the same length and all angles have the same degree (i.e., the polygon is both equilateral and equiangular). The formula for computing the area of a regular polygon is

Write a method that returns the area of a regular polygon using the following header:

public static double area(int n, double side)

Write a main method that prompts the user to enter the number of sides and the side of a regular polygon and displays its area.

Here is a sample run:
 
Enter the number of sides: 5

Enter the side:6.5

The area of the polygon is 72.690170
 

下面是参考答案代码:

// https://cn.fankuiba.com
import java.util.Scanner;

public class Ans6_36_page205 {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.print("Enter the side: ");
        double side = input.nextDouble();
        System.out.print("Enter the number of sides: ");
        int n = input.nextInt();
        System.out.println("The area of the pentagon is "+area(n,side));
    }
    public static double area(int n, double side) {
        return  (n * side * side) / (4 * Math.tan(Math.PI / 5));
    }
}

适用Java语言程序设计与数据结构(基础篇)(原书第11版)Java语言程序设计(基础篇)(原书第10/11版)更多内容

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